5y^2-20y+60=1

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Solution for 5y^2-20y+60=1 equation:


Simplifying
5y2 + -20y + 60 = 1

Reorder the terms:
60 + -20y + 5y2 = 1

Solving
60 + -20y + 5y2 = 1

Solving for variable 'y'.

Reorder the terms:
60 + -1 + -20y + 5y2 = 1 + -1

Combine like terms: 60 + -1 = 59
59 + -20y + 5y2 = 1 + -1

Combine like terms: 1 + -1 = 0
59 + -20y + 5y2 = 0

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
11.8 + -4y + y2 = 0

Move the constant term to the right:

Add '-11.8' to each side of the equation.
11.8 + -4y + -11.8 + y2 = 0 + -11.8

Reorder the terms:
11.8 + -11.8 + -4y + y2 = 0 + -11.8

Combine like terms: 11.8 + -11.8 = 0.0
0.0 + -4y + y2 = 0 + -11.8
-4y + y2 = 0 + -11.8

Combine like terms: 0 + -11.8 = -11.8
-4y + y2 = -11.8

The y term is -4y.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4y + 4 + y2 = -11.8 + 4

Reorder the terms:
4 + -4y + y2 = -11.8 + 4

Combine like terms: -11.8 + 4 = -7.8
4 + -4y + y2 = -7.8

Factor a perfect square on the left side:
(y + -2)(y + -2) = -7.8

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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